python for循环实现小功能以及推导式的分享
For 循环.一、使用for循环实现简单功能'''乘法表1--9乘法表for循环实现数字遍历'''for i in range(1,10): # 行中
for s in range(1,i+1):# 列中
print('%s X %s=%s '%(s,i,s*i),end ='')
print()'''
星星实现星星以三角形排列'''for i in range(1,9): # 行
for s in range(len(range(1,9))-i):
print(' ',end ='')
for n in range(1,2*i):# 列
print('*',end = '')
print() '''金额小写=>大写对循环数字进行拆分对数组合'''list_num = ['零','壹','贰','叁','肆','伍','陆','柒','捌','玖']list_U = ['园','拾','佰','仟','萬']input_num = input('输入数字：')len_U = len(input_num)for i in input_num: len_U -=1 print("{0}{1}".format(list_num,list_U),end='')print('整')
运行：E:\python_VS_code\directory[目录]>D://py3.6//python.exe e:/python_VS_code/directory[目录]/demo0802/py_for_mult.py1 X 1=11 X 2=2 2 X 2=41 X 3=3 2 X 3=6 3 X 3=91 X 4=4 2 X 4=8 3 X 4=12 4 X 4=161 X 5=5 2 X 5=10 3 X 5=15 4 X 5=20 5 X 5=251 X 6=6 2 X 6=12 3 X 6=18 4 X 6=24 5 X 6=30 6 X 6=361 X 7=7 2 X 7=14 3 X 7=21 4 X 7=28 5 X 7=35 6 X 7=42 7 X 7=491 X 8=8 2 X 8=16 3 X 8=24 4 X 8=32 5 X 8=40 6 X 8=48 7 X 8=56 8 X 8=641 X 9=9 2 X 9=18 3 X 9=27 4 X 9=36 5 X 9=45 6 X 9=54 7 X 9=63 8 X 9=72 9 X 9=81 * *** ***** ******* ******************** ****************************输入数字：1234壹仟贰佰叁拾肆园整
二、推导式：列表推导式：va=获得两个列表交集va3=va4=Va5=[ num for num in va3 if num in va4]获得并集va6=[ num for num inva3 if num not inva4 ]print(va6)print(va4+va6)获得差集va7=[ num for num inva4 if num not inva3 ]print(va7)-------------------------------------------------------------- # 获得0-99之间的 奇数的二倍值 va2= print('va2,',va2)生成器 对象（元组推导式）gen=( i for i in range(5)) print(gen) # for i in gen: # print(i)------------------------------------------------------------ 字典推导式mcase = {'a': 10, 'b': 34, 'A': 7, 'Z': 3,'B':20,'b':50}var={keyexcept:vaExcept forkey in 字典对象 }# if k.lower() in ['a','b','z']判断条件mcase_frequency = { k.lower(): mcase.get(k.lower(), 0) + mcase.get(k.upper(), 0) #第三部执行 for k in mcase.keys()#第一步 if k.lower() in ['a','b','z'] #第二部判断执行 true 执行第三部-------------------------------------------------------集合推导式mcase_key={key for key inmcase ifkey== key.lower()}
三，同样要求的三种不同解决方式'''统计字符串中数字和字母的个数1.使用异常处理非数字 try...except2.使用内置函数判定非数字isdigit()3.使用字符转换判断数字字母范围。ord() 字符转ascii码 chr() ascii码转字符'''str_for = 'adashgdkahfqa223354564'num = 0str_num = 0'''第一种'''for i in str_for: try: int(i) num +=1 except ValueError: str_num +=1print('数字:',num,'\n''字母:',str_num)'''第二种'''num1 = 0str_num1 = 0for i in str_for: if i.isdigit() == True: num1 +=1 else: str_num1 +=1print('数字:',num1,'\n''字母:',str_num1)'''第三种'''num2 = 0str_num2 = 0for i in str_for: if ord('0') < ord(i) <ord('9'): num2 +=1 elif ord('a') <= ord(i) <=ord('z') or ord('A') <= ord(i) <= ord('Z'): str_num2 += 1print('数字:',num2,'\n''字母:',str_num2)
四、推导式解决【金额大小写转换，字典推导式练习】list_num = ['零','壹','贰','叁','肆','伍','陆','柒','捌','玖']list_U = ['园','拾','佰','仟','萬']input_num = input('输入数字：')len_U = len(input_num)num_info = for i in num_info: len_U -=1 print('%s%s'%(list_num,list_U),end = '')print('整')'''字典对象初始化定义数据把 Key是 str类型长度大于等于5的信息获取用推导式'''dict_1 = {'a':12,123:'abcd','12345':True,'sadasdds':'18895','asd':'d'}dict_infer = {k:v for k,v in dict_1.items() if type(k) ==str and len(k) >= 5}print(dict_infer)
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