如何用Arduino完成随机抽题功能？

各位DF大佬们，用Arduino完成随机抽题功能，一个按键、两位数码管，按下按键后，随机生成01～12之间的一个数字，代表抽签的结果，如何实现，求解

自己测试看看，另外自己加个按键功能
int randNumber;

// Define the LED digit patters, from 0 - 9
// Note that these patterns are for common cathode displays
// For common anode displays, change the 1's to 0's and 0's to 1's
// 1 = LED on, 0 = LED off, in this order:

// Arduino pin: 2,3,4,5,6,7,8
byte seven_seg_digits[10][7] =
{
{ 1,1,1,1,1,1,0 },  // = 0
{ 0,1,1,0,0,0,0 },  // = 1
{ 1,1,0,1,1,0,1 },  // = 2
{ 1,1,1,1,0,0,1 },  // = 3
{ 0,1,1,0,0,1,1 },  // = 4
{ 1,0,1,1,0,1,1 },  // = 5
{ 1,0,1,1,1,1,1 },  // = 6
{ 1,1,1,0,0,0,0 },  // = 7
{ 1,1,1,1,1,1,1 },  // = 8
{ 1,1,1,0,0,1,1 }   // = 9
};

void setup() {               
  pinMode(2, OUTPUT);  
  pinMode(3, OUTPUT);
  pinMode(4, OUTPUT);
  pinMode(5, OUTPUT);
  pinMode(6, OUTPUT);
  pinMode(7, OUTPUT);
  pinMode(8, OUTPUT);
  pinMode(9, OUTPUT);
  writeDot(0);  // start with the "dot" off
}

void writeDot(byte dot) {
  digitalWrite(9, dot);
}
   
void sevenSegWrite(byte digit) {
  byte pin = 2;
  for (byte segCount = 0; segCount < 7; ++segCount) {
    digitalWrite(pin, seven_seg_digits[digit][segCount]);
    ++pin;
  }
}

void loop() {
// print number from 9 to 1
//  for (byte count = 10; count > 0; --count) {
//   delay(1000);
//   sevenSegWrite(count - 1);

// print a random number from 1 to 6
  randNumber = random(1, 7);
  Serial.println(randNumber);
  sevenSegWrite(randNumber);
  
  delay(1000);
}

gada888 发表于 2020-12-3 09:31
自己测试看看，另外自己加个按键功能
int randNumber;