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[教程] 【转帖】树莓派使用ULN2003 驱动板和28BYJ-48-5V减速步进电机

本教程教会你使用树莓派控制ULN2003 驱动板、28BYJ-48-5V减速步进电机。
所需材料：
母对母杜邦线：至少6根
ULN2003 驱动板 1个
28BYJ-48-5V减速步进电机  1个。
小白说明：步进电机在连结好驱动板，启动树莓派之后，在没启动程序时，驱动板上的灯是不会亮的。之前很多人认为不亮就怀疑板子有问题。
1、连线：
驱动板    树莓派
IN1    接 GPIO 17
IN2    接 GPIO 18
IN3    接 GPIO 21
IN4    接 GPIO 22

+       接 5V
-       接 GND

2、连结好线之后，进入打开树莓派桌面上的LXT终端（本文用的远程PUTTY），输入如下命令：sudo nano bujindianji.py
打开后，输入如下内容：

#-----------------------------------
# Name: bujindianji
# Created: 03/16/2014
#-----------------------------------
#!/usr/bin/env python

# Import required libraries
import time
import RPi.GPIO as GPIO

GPIO.setmode(GPIO.BCM)

StepPins = [17,18,27,22]

# Set all pins as output
for pin in StepPins:
  print "Setup pins"
  GPIO.setup(pin,GPIO.OUT)
  GPIO.output(pin, False)

# Define some settings
StepCounter = 0
WaitTime = 0.02

# Define simple sequence
StepCount1 = 4
Seq1 = []
Seq1 = range(0, StepCount1)
Seq1[0] = [1,0,0,0]
Seq1[1] = [0,1,0,0]
Seq1[2] = [0,0,1,0]
Seq1[3] = [0,0,0,1]

# Define advanced sequence
# as shown in manufacturers datasheet
StepCount2 = 8
Seq2 = []
Seq2 = range(0, StepCount2)
Seq2[0] = [1,0,0,0]
Seq2[1] = [1,1,0,0]
Seq2[2] = [0,1,0,0]
Seq2[3] = [0,1,1,0]
Seq2[4] = [0,0,1,0]
Seq2[5] = [0,0,1,1]
Seq2[6] = [0,0,0,1]
Seq2[7] = [1,0,0,1]

# Choose a sequence to use
Seq = Seq1
StepCount = StepCount1

# Start main loop
while 1==1:

  for pin in range(0, 4):
    xpin = StepPins[pin]
    if Seq[StepCounter][pin]!=0:
      print " Step %i Enable %i" %(StepCounter,xpin)
      GPIO.output(xpin, True)
    else:
      GPIO.output(xpin, False)

  StepCounter += 1

  # If we reach the end of the sequence
  # start again
  if (StepCounter==StepCount):
    StepCounter = 0
  if (StepCounter<0):
    StepCounter = StepCount

  # Wait before moving on
  time.sleep(WaitTime)
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